srand() and rand() Problem

ofcourse u'll get the same output because the rand() takes it seed at the first execution time but the srand(int) can chainge the output every time as in the code:
void main ()
{
cout<<srand(time(0));
}

or any thing like that,

Your original description is the correct way to do it. There is probably a subtle bug in your code. Try...

/* RAND.C: This program seeds the random-number generator
* with the time, then displays 10 random integers.
*/

#include <stdlib.h>
#include <stdio.h>
#include <time.h>

void main( void )
{
int i;

/* Seed the random-number generator with current time so that
* the numbers will be different every time we run.
*/
srand( (unsigned)time( NULL ) );

/* Display 10 numbers. */
for( i = 0; i < 10;i++ )
printf( " %6d\n", rand() );
}

Code re-printed without any permission whatsoever from the MSDN help files...

Does the program I posted give you different numbers each time?

If so, then it is a bug in your program...