c++ queries

Query1
--
There is a function that receives an array of integers and it returns an array with all duplicates removed. So lets say it received {1, 2, 2, 3} it would return {1, 2, 3}. If you could only use 5 (and only 5) test arrays to test this function, which 5 would you use? You can use std::vector or std::list to make your job simple using the unique standard algorithm.

The function that made the contents of your list/array unique is something like this -
void MakeMyArrayUnique (list <int> & lstIntegerArray)
{
lstIntegerArray.unique ();
}

This is how you would use it...

#include <list>
using namespace std;

int main(void)
{
// Create a list of integers using std::list
list <int> myIntegerArray;

// Insert integers into this array...
myIntegerArray.push_back (1);
myIntegerArray.push_back (2);
myIntegerArray.push_back (2);
myIntegerArray.push_back (3);

list <int> ::iterator iIntegerLocator;

// Print the original array
cout << "The original array is" << endl;
for ( iIntegerLocator = myIntegerArray.begin ()
; iIntegerLocator != myIntegerArray.end ()
; iIntegerLocator ++ )
cout << *iIntegerLocator << endl;

// REMOVE DUPLICATES
MakeMyArrayUnique (myIntegerArray);

// Print the new list
cout << "The array made unique is" << endl;
for ( iIntegerLocator = myIntegerArray.begin ()
; iIntegerLocator != myIntegerArray.end ()
; iIntegerLocator ++ )
cout << *iIntegerLocator << endl;

return 0;
}
You may also use std::vector, but, the advantage of std::list is that it contains a list::unique that does the job of making the list unique.

If you use std::vector, you will have to use the unique and also erase from <algorithm>.

This was solution to Query # 1...

i am trying to come up with some senareos for unit test cases..

For query 1 my test data would be what would be yours?.. Any suggestions appreciated. thx.

All values same
1) {1,1,1,1}
All values unique
2) {1,2,3,4}
First and last values same
3) {1,3,4,1}
Negative values in the list
4) {-1,2,1,3}
All values having duplicates.
5) {1,1,2,2}

thx.. Nice one , I never thought of ascii.