I have got a function for upload file. However, the functions makes use of the html form. But now, what i get is the path given by the client

function upload($path){
if (($_FILES["file"]["type"] == "image/gif") || ($_FILES["file"]["type"] == "image/pjpeg") && ($_FILES["file"]["size"] < 20000000)){
if ($_FILES["file"]["error"] > 0){
echo "Return Code: " . $_FILES["file"]["error"] . "<br />";
}
else
{
echo "Upload: " . $_FILES["file"]["name"] . "<br />";
echo "Type: " . $_FILES["file"]["type"] . "<br />";
echo "Size: " . ($_FILES["file"]["size"] / 1024) . " Kb<br />";
echo "Temp file: " . $_FILES["file"]["tmp_name"] . "<br />";

if (file_exists("upload/" . $_FILES["file"]["name"])){
echo $_FILES["file"]["name"] . " already exists. ";
}
else
{
move_uploaded_file($_FILES["file"]["tmp_name"], "upload/" . $_FILES["file"]["name"]);
echo "Stored in: " . "upload/" . $_FILES["file"]["name"];
}
}
}
else
{
echo "Invalid file";
}

}

i would like to know how to do if i didnt use the HTML form to upload file, how to upload file with the client directory?

Thank you.