Assembling 32 bit value
byte byVal=10; //16#0A
sbyte sbyVal=-1; //16#FF
UInt16 usVal=512 //16#0200;would then result in the following 32 bit variable 16#0AFF0200 !
Anyone ?
[322 byte] By [zvenny] at [2007-11-20 11:31:46] 
I'm looking for a way to store a byte , sbyte and UInt16 in a 32 bit variable in a way that the hex representation looks like bytesbyteuInt16. e.g.
byte byVal=10; //16#0A
sbyte sbyVal=-1; //16#FF
UInt16 usVal=512 //16#0200;would then result in the following 32 bit variable 16#0AFF0200 !
Anyone ?
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»» cany anyone simplify this code? (multiplying the product of two vectors)
# 1 Re: Assembling 32 bit value
Maybe the Conversion.Hex() method gives you a starting point.torrud at 2007-11-9 11:36:44 >
