Question on CIN
Hey guess, sorry for the rookie questions. I'm new to this, I tried a search and really dont even know what I'm looking for, or what this would be called.
I'm trying to make a numerology report, but I'm not looking for complete help.
I just have a simple question reguarding my cin statement.
Heres what I have so far:
int year;
int month;
int year;
cout << "Enter the Birth Date seperated by dashes. (MM-DD-YYYY): "<<endl;
cin >> month >> date >> year;
What I'm trying to do is with a single cin sepereate the MM DD and YYYY.
Is that possible?
[679 byte] By [
Flakester] at [2007-11-20 11:42:58]
# 1 Re: Question on CIN
Well have you tried it out?
It will work if you enter the birth date separeted with spaces. Just try it out man :)
Btw: You are redefining "year", I think you forgot the declare date,
Laitinen
# 2 Re: Question on CIN
To do so, the best way will probably to read a string in the flow with a cin.getbuf method.
So, you'll be able to parse manually the string.
For instance,
#include <iostream>
using namespace std;
int main(int , char *[])
{
char buf[256];
cin.getbuf(buf, 255);
int day, month, year;
if(buf[2]!='/' || buf[5]!='/')
cerr << "You should type the date with the following pattern: dd/mm/yyyy" << endl;
else
{
buf[2] = '\0';
buf[5] = '\0';
day = atoi(buf);
month = atoi(buf+3);
year = atoi(buf+6);
}
}
Write this without testing, I hope there's no error.
Oups, this is the french date format.
